Question
Answer
$$\dfrac{9x^3}{7}\cdot\dfrac{6}{5x^3}=\dfrac{54x^3}{35x^3}$$
Explanation
| $$ \begin{aligned}\frac{9x^3}{7}\cdot\frac{6}{5x^3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{54x^3}{35x^3}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{9x^3}{7} $ by $ \dfrac{6}{5x^3} $ to get $ \dfrac{ 54x^3 }{ 35x^3 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{9x^3}{7} \cdot \frac{6}{5x^3} & \xlongequal{\text{Step 1}} \frac{ 9x^3 \cdot 6 }{ 7 \cdot 5x^3 } \xlongequal{\text{Step 2}} \frac{ 54x^3 }{ 35x^3 } \end{aligned} $$ |
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Simplify Rational Expressions