Question
Answer
$$\dfrac{\dfrac{6x^2}{5}}{\dfrac{8x^3}{3}}=\dfrac{18x^2}{40x^3}$$
Explanation
| $$ \begin{aligned}\frac{\frac{6x^2}{5}}{\frac{8x^3}{3}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{18x^2}{40x^3}\end{aligned} $$ | |
| ① | Divide $ \dfrac{6x^2}{5} $ by $ \dfrac{8x^3}{3} $ to get $ \dfrac{ 18x^2 }{ 40x^3 } $. Step 1: To divide rational expressions, multiply the first fraction by the reciprocal of the second fraction. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{ \frac{6x^2}{5} }{ \frac{\color{blue}{8x^3}}{\color{blue}{3}} } & \xlongequal{\text{Step 1}} \frac{6x^2}{5} \cdot \frac{\color{blue}{3}}{\color{blue}{8x^3}} = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ 6x^2 \cdot 3 }{ 5 \cdot 8x^3 } \xlongequal{\text{Step 3}} \frac{ 18x^2 }{ 40x^3 } \end{aligned} $$ |
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Simplify Rational Expressions