Question
Answer
$$\dfrac{44x^7y^4}{5xy^2}\dfrac{12xy^5}{22x^5y^3}=\dfrac{528x^8y^9}{110x^6y^5}$$
Explanation
| $$ \begin{aligned}\frac{44x^7y^4}{5xy^2}\frac{12xy^5}{22x^5y^3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{528x^8y^9}{110x^6y^5}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{44x^7y^4}{5xy^2} $ by $ \dfrac{12xy^5}{22x^5y^3} $ to get $ \dfrac{ 528x^8y^9 }{ 110x^6y^5 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{44x^7y^4}{5xy^2} \cdot \frac{12xy^5}{22x^5y^3} & \xlongequal{\text{Step 1}} \frac{ 44x^7y^4 \cdot 12xy^5 }{ 5xy^2 \cdot 22x^5y^3 } = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ 528x^8y^9 }{ 110x^6y^5 } \end{aligned} $$ |
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Simplify Rational Expressions