Question
Answer
$$\dfrac{3ac^3x^3}{8a^2bf}\dfrac{12ab^2c}{18ab^3c^2f}=\dfrac{36a^2b^2c^4x^3}{144a^3b^4c^2f^2}$$
Explanation
| $$ \begin{aligned}\frac{3ac^3x^3}{8a^2bf}\frac{12ab^2c}{18ab^3c^2f}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{36a^2b^2c^4x^3}{144a^3b^4c^2f^2}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{3ac^3x^3}{8a^2bf} $ by $ \dfrac{12ab^2c}{18ab^3c^2f} $ to get $ \dfrac{ 36a^2b^2c^4x^3 }{ 144a^3b^4c^2f^2 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{3ac^3x^3}{8a^2bf} \cdot \frac{12ab^2c}{18ab^3c^2f} & \xlongequal{\text{Step 1}} \frac{ 3ac^3x^3 \cdot 12ab^2c }{ 8a^2bf \cdot 18ab^3c^2f } = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ 36a^2b^2c^4x^3 }{ 144a^3b^4c^2f^2 } \end{aligned} $$ |
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