Question
Answer
$$\dfrac{2m^2-2m-40}{3m+12}=\dfrac{2m-10}{3}$$
Explanation
| $$ \begin{aligned}\frac{2m^2-2m-40}{3m+12}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2m-10}{3}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2m^2-2m-40}{3m+12} $ to $ \dfrac{2m-10}{3} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{m+4}$. $$ \begin{aligned} \frac{2m^2-2m-40}{3m+12} & =\frac{ \left( 2m-10 \right) \cdot \color{blue}{ \left( m+4 \right) }}{ 3 \cdot \color{blue}{ \left( m+4 \right) }} = \\[1ex] &= \frac{2m-10}{3} \end{aligned} $$ |
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Simplify Rational Expressions