Question
$$x^4+4x^3-41x^2-176x = 0$$
Answer
$$ x = 0 $$
Explanation
In order to solve $ \color{blue}{ x^{4}+4x^{3}-41x^{2}-176x = 0 } $, first we need to factor our $ x $.
$$ x^{4}+4x^{3}-41x^{2}-176x = x \left( x^{3}+4x^{2}-41x-176 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ x^{3}+4x^{2}-41x-176 = 0$.
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using qubic formulas.
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