Question
$$6x^2+203(2x^2+2x)\cdot6x^2+26 = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 6x^2+203(2x^2+2x)\cdot6x^2+26 &= 0&& \text{simplify left side} \\[1 em]6x^2+(406x^2+406x)\cdot6x^2+26 &= 0&& \\[1 em]6x^2+(2436x^2+2436x)x^2+26 &= 0&& \\[1 em]6x^2+2436x^4+2436x^3+26 &= 0&& \\[1 em]2436x^4+2436x^3+6x^2+26 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
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Equations Solver