Question
$$2x^5-4x^3-6x = 0$$
Answer
$$ x = 0 $$
Explanation
In order to solve $ \color{blue}{ 2x^{5}-4x^{3}-6x = 0 } $, first we need to factor our $ x $.
$$ 2x^{5}-4x^{3}-6x = x \left( 2x^{4}-4x^{2}-6 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 2x^{4}-4x^{2}-6 = 0$.
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
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