Question
$$13x^3+2x\cdot3-7(x^2+9)^2 = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 13x^3+2x\cdot3-7(x^2+9)^2 &= 0&& \text{simplify left side} \\[1 em]13x^3+6x-7(x^2+9)^2 &= 0&& \\[1 em]13x^3+6x-7(x^4+18x^2+81) &= 0&& \\[1 em]13x^3+6x-(7x^4+126x^2+567) &= 0&& \\[1 em]13x^3+6x-7x^4-126x^2-567 &= 0&& \\[1 em]-7x^4+13x^3-126x^2+6x-567 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
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Equations Solver