Question
$$(x+1)x(x-2) = 10$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (x+1)x(x-2) &= 10&& \text{simplify left side} \\[1 em](x^2+x)(x-2) &= 10&& \\[1 em]x^3-2x^2+x^2-2x &= 10&& \\[1 em]x^3-x^2-2x &= 10&& \text{move all terms to the left hand side } \\[1 em]x^3-x^2-2x-10 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using qubic formulas.
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Equations Solver