Question
Multiply polynomial $ \, \color{blue}{ x^2+3 } \, $ by $ \, \color{orangered}{ x+6 }$.
Answer
$$ \left( \color{blue}{x^2+3} \right) \cdot \left( \color{orangered}{x+6} \right) = x^3+6x^2+3x+18 $$
Explanation
In this example we are multiplying two binomials so FOIL method can be used.
$$ \begin{aligned} \left( \color{blue}{ x^2+3}\right) \cdot \left( \color{orangered}{ x+6}\right) &= \underbrace{ \color{blue}{x^2} \cdot \color{orangered}{x} }_{\text{FIRST}} + \underbrace{ \color{blue}{x^2} \cdot \color{orangered}{6} }_{\text{OUTER}} + \underbrace{ \color{blue}{3} \cdot \color{orangered}{x} }_{\text{INNER}} + \underbrace{ \color{blue}{3} \cdot \color{orangered}{6} }_{\text{LAST}} = \\ &= x^3 + 6x^2 + 3x + 18 = \\ &= x^3 + 6x^2 + 3x + 18 = \\ &= x^3+6x^2+3x+18; \end{aligned} $$This page was created using
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