Question
Multiply polynomial $ \, \color{blue}{ 6x^2-3x } \, $ by $ \, \color{orangered}{ 3x }$.
Answer
$$ \left( \color{blue}{6x^2-3x} \right) \cdot \color{orangered}{3x} = 18x^3-9x^2 $$
Explanation
We can use distribution property to multiply the polynomial by the monomial.
$$ \begin{aligned} \left( 6x^2-3x \right) \cdot \color{orangered}{3x} &= 6x^2 \cdot \color{orangered}{3x} + \left( -3x\right) \cdot \color{orangered}{3x} = \\ &= 18x^3-9x^2 \end{aligned} $$This page was created using
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