Question
Multiply polynomial $ \, \color{blue}{ 2j^2 } \, $ by $ \, \color{orangered}{ 3j^2-3j-1 }$.
Answer
$$ \color{blue}{2j^2} \cdot \left( \color{orangered}{3j^2-3j-1} \right) = 6j^4-6j^3-2j^2 $$
Explanation
We can use distribution property to multiply the polynomial by the monomial.
$$ \begin{aligned} \color{blue}{2j^2} \cdot \left( 3j^2-3j-1 \right) &= \color{blue}{2j^2} \cdot 3j^2 + \color{blue}{2j^2} \cdot \left( -3j\right) + \color{blue}{2j^2} \cdot \left( -1\right) = \\ &= 6j^4-6j^3-2j^2 \end{aligned} $$This page was created using
Polynomial Operations Calculator