In this example we are multiplying two binomials so FOIL method can be used.

$$ \begin{aligned} \left( \color{blue}{ 2p^2-11p}\right) \cdot \left( \color{orangered}{ 3p-4}\right) &= \underbrace{ \color{blue}{2p^2} \cdot \color{orangered}{3p} }_{\text{FIRST}} + \underbrace{ \color{blue}{2p^2} \cdot \left( \color{orangered}{-4} \right) }_{\text{OUTER}} + \underbrace{ \left( \color{blue}{-11p} \right) \cdot \color{orangered}{3p} }_{\text{INNER}} + \underbrace{ \left( \color{blue}{-11p} \right) \cdot \left( \color{orangered}{-4} \right) }_{\text{LAST}} = \\ &= 6p^3 + \left( -8p^2\right) + \left( -33p^2\right) + 44p = \\ &= 6p^3 + \left( -8p^2\right) + \left( -33p^2\right) + 44p = \\ &= 6p^3-41p^2+44p; \end{aligned} $$

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