Question
Answer
$$x^5(1+x^{10}-2x^5)(1-x)^{-4}=(x^5+x^{15}-2x^{10})(1-x)^{-4}$$
Explanation
| $$ \begin{aligned}x^5(1+x^{10}-2x^5)(1-x)^{-4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(x^5+x^{15}-2x^{10})(1-x)^{-4}\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{x^5} $ by $ \left( 1+x^{10}-2x^5\right) $ $$ \color{blue}{x^5} \cdot \left( 1+x^{10}-2x^5\right) = x^5+x^{15}-2x^{10} $$ |
This page was created using
Simplify polynomials calculator