Question
Answer
$$x^4-3(x^2+x)+2x=x^4-3x^2-x$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x^4-3(x^2+x)+2x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^4-(3x^2+3x)+2x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^4-3x^2-3x+2x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}x^4-3x^2-x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( x^2+x\right) $ $$ \color{blue}{3} \cdot \left( x^2+x\right) = 3x^2+3x $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 3x^2+3x \right) = -3x^2-3x $$ |
| ③ | Combine like terms: $$ x^4-3x^2 \color{blue}{-3x} + \color{blue}{2x} = x^4-3x^2 \color{blue}{-x} $$ |
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