Question
Answer
$$x^2-x-\dfrac{2}{2}v^2-2=-v^2+x^2-x-2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x^2-x-\frac{2}{2}v^2-2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2-x - \frac{ 2 : \color{orangered}{ 2 } }{ 2 : \color{orangered}{ 2 }} \cdot v^2 - 2 \xlongequal{ } \\[1 em] & \xlongequal{ }x^2-x-\frac{1}{1}v^2-2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-x-v^2-2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-v^2+x^2-x-2\end{aligned} $$ | |
| ① | Divide both the top and bottom numbers by $ \color{orangered}{ 2 } $. |
| ② | Remove 1 from denominator. |
| ③ | Combine like terms: $$ -v^2+x^2-x-2 = -v^2+x^2-x-2 $$ |
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