Question
Answer
$$x(x-2)(x+8)=x^3+6x^2-16x$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x(x-2)(x+8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(x^2-2x)(x+8) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^3+8x^2-2x^2-16x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}x^3+6x^2-16x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{x} $ by $ \left( x-2\right) $ $$ \color{blue}{x} \cdot \left( x-2\right) = x^2-2x $$ |
| ② | Multiply each term of $ \left( \color{blue}{x^2-2x}\right) $ by each term in $ \left( x+8\right) $. $$ \left( \color{blue}{x^2-2x}\right) \cdot \left( x+8\right) = x^3+8x^2-2x^2-16x $$ |
| ③ | Combine like terms: $$ x^3+ \color{blue}{8x^2} \color{blue}{-2x^2} -16x = x^3+ \color{blue}{6x^2} -16x $$ |
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