Tap the blue circles to see an explanation.
| $$ \begin{aligned}x(x-1)^2(x-2)^2(x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x(x^2-2x+1)(x^2-4x+4)(x-3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(x^3-2x^2+x)(x^2-4x+4)(x-3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}(x^5-6x^4+13x^3-12x^2+4x)(x-3) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} \htmlClass{explanationCircle explanationCircle6}{\textcircled {6}} } }}}x^6-9x^5+31x^4-51x^3+40x^2-12x\end{aligned} $$ | |
| ① | Find $ \left(x-1\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ x } $ and $ B = \color{red}{ 1 }$. $$ \begin{aligned}\left(x-1\right)^2 = \color{blue}{x^2} -2 \cdot x \cdot 1 + \color{red}{1^2} = x^2-2x+1\end{aligned} $$Find $ \left(x-2\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ x } $ and $ B = \color{red}{ 2 }$. $$ \begin{aligned}\left(x-2\right)^2 = \color{blue}{x^2} -2 \cdot x \cdot 2 + \color{red}{2^2} = x^2-4x+4\end{aligned} $$ |
| ② | Multiply $ \color{blue}{x} $ by $ \left( x^2-2x+1\right) $ $$ \color{blue}{x} \cdot \left( x^2-2x+1\right) = x^3-2x^2+x $$ |
| ③ | Multiply each term of $ \left( \color{blue}{x^3-2x^2+x}\right) $ by each term in $ \left( x^2-4x+4\right) $. $$ \left( \color{blue}{x^3-2x^2+x}\right) \cdot \left( x^2-4x+4\right) = x^5-4x^4+4x^3-2x^4+8x^3-8x^2+x^3-4x^2+4x $$ |
| ④ | Combine like terms: $$ x^5 \color{blue}{-4x^4} + \color{red}{4x^3} \color{blue}{-2x^4} + \color{green}{8x^3} \color{orange}{-8x^2} + \color{green}{x^3} \color{orange}{-4x^2} +4x = \\ = x^5 \color{blue}{-6x^4} + \color{green}{13x^3} \color{orange}{-12x^2} +4x $$ |
| ⑤ | Multiply each term of $ \left( \color{blue}{x^5-6x^4+13x^3-12x^2+4x}\right) $ by each term in $ \left( x-3\right) $. $$ \left( \color{blue}{x^5-6x^4+13x^3-12x^2+4x}\right) \cdot \left( x-3\right) = \\ = x^6-3x^5-6x^5+18x^4+13x^4-39x^3-12x^3+36x^2+4x^2-12x $$ |
| ⑥ | Combine like terms: $$ x^6 \color{blue}{-3x^5} \color{blue}{-6x^5} + \color{red}{18x^4} + \color{red}{13x^4} \color{green}{-39x^3} \color{green}{-12x^3} + \color{orange}{36x^2} + \color{orange}{4x^2} -12x = \\ = x^6 \color{blue}{-9x^5} + \color{red}{31x^4} \color{green}{-51x^3} + \color{orange}{40x^2} -12x $$ |