Question
Answer
$$x(2x+1)+4(x-5)=2x^2+5x-20$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}x(2x+1)+4(x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2+x+4x-20 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2+5x-20\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{x} $ by $ \left( 2x+1\right) $ $$ \color{blue}{x} \cdot \left( 2x+1\right) = 2x^2+x $$Multiply $ \color{blue}{4} $ by $ \left( x-5\right) $ $$ \color{blue}{4} \cdot \left( x-5\right) = 4x-20 $$ |
| ② | Combine like terms: $$ 2x^2+ \color{blue}{x} + \color{blue}{4x} -20 = 2x^2+ \color{blue}{5x} -20 $$ |
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