Question
Answer
$$pi(3x)^2-pix^2=8ipx^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}pi(3x)^2-pix^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}pi\cdot9x^2-pix^2 \xlongequal{ } \\[1 em] & \xlongequal{ }9ipx^2-pix^2 \xlongequal{ } \\[1 em] & \xlongequal{ }9ipx^2-ipx^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}8ipx^2\end{aligned} $$ | |
| ① | $$ \left( 3x \right)^2 = 3^2x^2 = 9x^2 $$ |
| ② | Combine like terms: $$ \color{blue}{9ipx^2} \color{blue}{-ipx^2} = \color{blue}{8ipx^2} $$ |
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