Tap the blue circles to see an explanation.
| $$ \begin{aligned}n+m^2\frac{(n-1)(n-1+1)}{2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}n+m^2\frac{n^2-n+n-n+1-1}{2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}n+m^2\frac{n^2-n}{2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}n+\frac{m^2n^2-m^2n}{2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{m^2n^2-m^2n+2n}{2}\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{n-1}\right) $ by each term in $ \left( n -\cancel{1}+ \cancel{1}\right) $. $$ \left( \color{blue}{n-1}\right) \cdot \left( n -\cancel{1}+ \cancel{1}\right) = \\ = n^2 -\cancel{n}+ \cancel{n} -\cancel{n}+ \cancel{1} -\cancel{1} $$ |
| ② | Combine like terms: $$ n^2 \, \color{blue}{ -\cancel{n}} \,+ \, \color{green}{ \cancel{n}} \, \, \color{green}{ -\cancel{n}} \,+ \, \color{blue}{ \cancel{1}} \, \, \color{blue}{ -\cancel{1}} \, = n^2 \color{green}{-n} $$ |
| ③ | Multiply $m^2$ by $ \dfrac{n^2-n}{2} $ to get $ \dfrac{ m^2n^2-m^2n }{ 2 } $. Step 1: Write $ m^2 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} m^2 \cdot \frac{n^2-n}{2} & \xlongequal{\text{Step 1}} \frac{m^2}{\color{red}{1}} \cdot \frac{n^2-n}{2} \xlongequal{\text{Step 2}} \frac{ m^2 \cdot \left( n^2-n \right) }{ 1 \cdot 2 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ m^2n^2-m^2n }{ 2 } \end{aligned} $$ |
| ④ | Add $n$ and $ \dfrac{m^2n^2-m^2n}{2} $ to get $ \dfrac{ \color{purple}{ m^2n^2-m^2n+2n } }{ 2 }$. Step 1: Write $ n $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: To add raitonal expressions, both fractions must have the same denominator. |