Question
Answer
$$n(n-1)\dfrac{n^{2/n}-2n^{1/n}+1}{2}=(1n^2-n)\dfrac{n^{2/n}-2n^{1/n}+1}{2}$$
Explanation
| $$ \begin{aligned}n(n-1)\frac{n^{2/n}-2n^{1/n}+1}{2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(1n^2-n)\frac{n^{2/n}-2n^{1/n}+1}{2}\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{n} $ by $ \left( n-1\right) $ $$ \color{blue}{n} \cdot \left( n-1\right) = n^2-n $$ |
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