Question
Answer
$$k(k-3)-m(m-3)=k^2-m^2-3k+3m$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}k(k-3)-m(m-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}k^2-3k-(1m^2-3m) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}k^2-3k-m^2+3m \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}k^2-m^2-3k+3m\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{k} $ by $ \left( k-3\right) $ $$ \color{blue}{k} \cdot \left( k-3\right) = k^2-3k $$Multiply $ \color{blue}{m} $ by $ \left( m-3\right) $ $$ \color{blue}{m} \cdot \left( m-3\right) = m^2-3m $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( m^2-3m \right) = -m^2+3m $$ |
| ③ | Combine like terms: $$ k^2-m^2-3k+3m = k^2-m^2-3k+3m $$ |
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