Question
Answer
$$k(k-1)=k^2-k$$
Explanation
| $$ \begin{aligned}k(k-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}k^2-k\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{k} $ by $ \left( k-1\right) $ $$ \color{blue}{k} \cdot \left( k-1\right) = k^2-k $$ |
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