Question
Answer
$$9z\cdot(3-6z)+13z^2=-41z^2+27z$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}9z\cdot(3-6z)+13z^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}27z-54z^2+13z^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-41z^2+27z\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{9z} $ by $ \left( 3-6z\right) $ $$ \color{blue}{9z} \cdot \left( 3-6z\right) = 27z-54z^2 $$ |
| ② | Combine like terms: $$ 27z \color{blue}{-54z^2} + \color{blue}{13z^2} = \color{blue}{-41z^2} +27z $$ |
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