Question
Answer
$$9x^2(-3x^3+4x-5)=-27x^5+36x^3-45x^2$$
Explanation
| $$ \begin{aligned}9x^2(-3x^3+4x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-27x^5+36x^3-45x^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{9x^2} $ by $ \left( -3x^3+4x-5\right) $ $$ \color{blue}{9x^2} \cdot \left( -3x^3+4x-5\right) = -27x^5+36x^3-45x^2 $$ |
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