| $$ \begin{aligned}9(x^2-5x-6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9x^2-45x-54\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{9} $ by $ \left( x^2-5x-6\right) $ $$ \color{blue}{9} \cdot \left( x^2-5x-6\right) = 9x^2-45x-54 $$ |