Question
Answer
$$8x\cdot(1-x)=-8x^2+8x$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}8x\cdot(1-x)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8x-8x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-8x^2+8x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{8x} $ by $ \left( 1-x\right) $ $$ \color{blue}{8x} \cdot \left( 1-x\right) = 8x-8x^2 $$ |
| ② | Combine like terms: $$ -8x^2+8x = -8x^2+8x $$ |
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