Question
Answer
$$6z^2(7z^2+3z-2)=42z^4+18z^3-12z^2$$
Explanation
| $$ \begin{aligned}6z^2(7z^2+3z-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}42z^4+18z^3-12z^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{6z^2} $ by $ \left( 7z^2+3z-2\right) $ $$ \color{blue}{6z^2} \cdot \left( 7z^2+3z-2\right) = 42z^4+18z^3-12z^2 $$ |
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