Question
Answer
$$6+2x^2-3x-4x-x^2=x^2-7x+6$$
Explanation
| $$ \begin{aligned}6+2x^2-3x-4x-x^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2-7x+6\end{aligned} $$ | |
| ① | Combine like terms: $$ 6+ \color{blue}{2x^2} \color{red}{-3x} \color{red}{-4x} \color{blue}{-x^2} = \color{blue}{x^2} \color{red}{-7x} +6 $$ |
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