Question
Answer
$$6(y-1)+3(4y+5)=18y+9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}6(y-1)+3(4y+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6y-6+12y+15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}18y+9\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{6} $ by $ \left( y-1\right) $ $$ \color{blue}{6} \cdot \left( y-1\right) = 6y-6 $$Multiply $ \color{blue}{3} $ by $ \left( 4y+5\right) $ $$ \color{blue}{3} \cdot \left( 4y+5\right) = 12y+15 $$ |
| ② | Combine like terms: $$ \color{blue}{6y} \color{red}{-6} + \color{blue}{12y} + \color{red}{15} = \color{blue}{18y} + \color{red}{9} $$ |
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