Question
Answer
$$5z+3\cdot(4-2z)=-z+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5z+3\cdot(4-2z)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}5z+12-6z \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-z+12\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( 4-2z\right) $ $$ \color{blue}{3} \cdot \left( 4-2z\right) = 12-6z $$ |
| ② | Combine like terms: $$ \color{blue}{5z} +12 \color{blue}{-6z} = \color{blue}{-z} +12 $$ |
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