Tap the blue circles to see an explanation.
| $$ \begin{aligned}5x(x+2)-2(4x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}5x^2+10x-(8x-10) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}5x^2+10x-8x+10 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}5x^2+2x+10\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{5x} $ by $ \left( x+2\right) $ $$ \color{blue}{5x} \cdot \left( x+2\right) = 5x^2+10x $$Multiply $ \color{blue}{2} $ by $ \left( 4x-5\right) $ $$ \color{blue}{2} \cdot \left( 4x-5\right) = 8x-10 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 8x-10 \right) = -8x+10 $$ |
| ③ | Combine like terms: $$ 5x^2+ \color{blue}{10x} \color{blue}{-8x} +10 = 5x^2+ \color{blue}{2x} +10 $$ |