Question
Answer
$$5r^2s^3(r+3)-4rs^2(r+3)=5r^3s^3+15r^2s^3-4r^2s^2-12rs^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5r^2s^3(r+3)-4rs^2(r+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}5r^3s^3+15r^2s^3-(4r^2s^2+12rs^2) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}5r^3s^3+15r^2s^3-4r^2s^2-12rs^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{5r^2s^3} $ by $ \left( r+3\right) $ $$ \color{blue}{5r^2s^3} \cdot \left( r+3\right) = 5r^3s^3+15r^2s^3 $$Multiply $ \color{blue}{4rs^2} $ by $ \left( r+3\right) $ $$ \color{blue}{4rs^2} \cdot \left( r+3\right) = 4r^2s^2+12rs^2 $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4r^2s^2+12rs^2 \right) = -4r^2s^2-12rs^2 $$ |
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