Question
Answer
$$5r(4r\cdot2-r+6)=35r^2+30r$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5r(4r\cdot2-r+6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}5r(8r-r+6) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}5r(7r+6) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}35r^2+30r\end{aligned} $$ | |
| ① | $$ 4 r \cdot 2 = 8 r $$ |
| ② | Combine like terms: $$ \color{blue}{8r} \color{blue}{-r} +6 = \color{blue}{7r} +6 $$ |
| ③ | Multiply $ \color{blue}{5r} $ by $ \left( 7r+6\right) $ $$ \color{blue}{5r} \cdot \left( 7r+6\right) = 35r^2+30r $$ |
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