Question
Answer
$$5r(4r^2-r+6)=20r^3-5r^2+30r$$
Explanation
| $$ \begin{aligned}5r(4r^2-r+6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}20r^3-5r^2+30r\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{5r} $ by $ \left( 4r^2-r+6\right) $ $$ \color{blue}{5r} \cdot \left( 4r^2-r+6\right) = 20r^3-5r^2+30r $$ |
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