Question
Answer
$$5(s-4)(s+6)=5s^2+10s-120$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5(s-4)(s+6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(5s-20)(s+6) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}5s^2+30s-20s-120 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}5s^2+10s-120\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{5} $ by $ \left( s-4\right) $ $$ \color{blue}{5} \cdot \left( s-4\right) = 5s-20 $$ |
| ② | Multiply each term of $ \left( \color{blue}{5s-20}\right) $ by each term in $ \left( s+6\right) $. $$ \left( \color{blue}{5s-20}\right) \cdot \left( s+6\right) = 5s^2+30s-20s-120 $$ |
| ③ | Combine like terms: $$ 5s^2+ \color{blue}{30s} \color{blue}{-20s} -120 = 5s^2+ \color{blue}{10s} -120 $$ |
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