Question
Answer
$$4y^7(3y^9+7y)=12y^{16}+28y^8$$
Explanation
| $$ \begin{aligned}4y^7(3y^9+7y)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12y^{16}+28y^8\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4y^7} $ by $ \left( 3y^9+7y\right) $ $$ \color{blue}{4y^7} \cdot \left( 3y^9+7y\right) = 12y^{16}+28y^8 $$ |
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