| $$ \begin{aligned}4y^2(y^2+2y)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4y^4+8y^3\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4y^2} $ by $ \left( y^2+2y\right) $ $$ \color{blue}{4y^2} \cdot \left( y^2+2y\right) = 4y^4+8y^3 $$ |