Question
Answer
$$4(4a-1)+5a-1=21a-5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4(4a-1)+5a-1& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}16a-4+5a-1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}21a-5\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{4} $ by $ \left( 4a-1\right) $ $$ \color{blue}{4} \cdot \left( 4a-1\right) = 16a-4 $$ |
| ② | Combine like terms: $$ \color{blue}{16a} \color{red}{-4} + \color{blue}{5a} \color{red}{-1} = \color{blue}{21a} \color{red}{-5} $$ |
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