Question
Answer
$$3y+4y^2+4y-(2y^2-6)=2y^2+7y+6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3y+4y^2+4y-(2y^2-6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4y^2+7y-(2y^2-6) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4y^2+7y-2y^2+6 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}2y^2+7y+6\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{3y} +4y^2+ \color{blue}{4y} = 4y^2+ \color{blue}{7y} $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 2y^2-6 \right) = -2y^2+6 $$ |
| ③ | Combine like terms: $$ \color{blue}{4y^2} +7y \color{blue}{-2y^2} +6 = \color{blue}{2y^2} +7y+6 $$ |
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