| $$ \begin{aligned}3xy(x^2+y^2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^3y+3xy^3\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3xy} $ by $ \left( x^2+y^2\right) $ $$ \color{blue}{3xy} \cdot \left( x^2+y^2\right) = 3x^3y+3xy^3 $$ |