| $$ \begin{aligned}3x^2(x-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^3-12x^2\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3x^2} $ by $ \left( x-4\right) $ $$ \color{blue}{3x^2} \cdot \left( x-4\right) = 3x^3-12x^2 $$ |