Question
Answer
$$3x^2(x+y)+2x^2(3x+5y)=9x^3+13x^2y$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3x^2(x+y)+2x^2(3x+5y)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^3+3x^2y+6x^3+10x^2y \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}9x^3+13x^2y\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3x^2} $ by $ \left( x+y\right) $ $$ \color{blue}{3x^2} \cdot \left( x+y\right) = 3x^3+3x^2y $$Multiply $ \color{blue}{2x^2} $ by $ \left( 3x+5y\right) $ $$ \color{blue}{2x^2} \cdot \left( 3x+5y\right) = 6x^3+10x^2y $$ |
| ② | Combine like terms: $$ \color{blue}{3x^3} + \color{red}{3x^2y} + \color{blue}{6x^3} + \color{red}{10x^2y} = \color{blue}{9x^3} + \color{red}{13x^2y} $$ |
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