Question
Answer
$$3x^2\cdot(1+3x)-2x(3x-2)=9x^3-3x^2+4x$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3x^2\cdot(1+3x)-2x(3x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^2+9x^3-(6x^2-4x) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3x^2+9x^3-6x^2+4x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}9x^3-3x^2+4x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3x^2} $ by $ \left( 1+3x\right) $ $$ \color{blue}{3x^2} \cdot \left( 1+3x\right) = 3x^2+9x^3 $$Multiply $ \color{blue}{2x} $ by $ \left( 3x-2\right) $ $$ \color{blue}{2x} \cdot \left( 3x-2\right) = 6x^2-4x $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( 6x^2-4x \right) = -6x^2+4x $$ |
| ③ | Combine like terms: $$ \color{blue}{3x^2} +9x^3 \color{blue}{-6x^2} +4x = 9x^3 \color{blue}{-3x^2} +4x $$ |
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