Question
Answer
$$3x(x^3-5x^2+4)=3x^4-15x^3+12x$$
Explanation
| $$ \begin{aligned}3x(x^3-5x^2+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^4-15x^3+12x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3x} $ by $ \left( x^3-5x^2+4\right) $ $$ \color{blue}{3x} \cdot \left( x^3-5x^2+4\right) = 3x^4-15x^3+12x $$ |
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