Question
Answer
$$3x(2x-4)-x(t+5)=-tx+6x^2-17x$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3x(2x-4)-x(t+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2-12x-(1tx+5x) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^2-12x-tx-5x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-tx+6x^2-17x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3x} $ by $ \left( 2x-4\right) $ $$ \color{blue}{3x} \cdot \left( 2x-4\right) = 6x^2-12x $$Multiply $ \color{blue}{x} $ by $ \left( t+5\right) $ $$ \color{blue}{x} \cdot \left( t+5\right) = tx+5x $$ |
| ② | Remove the parentheses by changing the sign of each term within them. $$ - \left( tx+5x \right) = -tx-5x $$ |
| ③ | Combine like terms: $$ 6x^2 \color{blue}{-12x} -tx \color{blue}{-5x} = -tx+6x^2 \color{blue}{-17x} $$ |
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