Question
Answer
$$3x(2x^2+4x-6)=6x^3+12x^2-18x$$
Explanation
| $$ \begin{aligned}3x(2x^2+4x-6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^3+12x^2-18x\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3x} $ by $ \left( 2x^2+4x-6\right) $ $$ \color{blue}{3x} \cdot \left( 2x^2+4x-6\right) = 6x^3+12x^2-18x $$ |
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