Question
Answer
$$3a^2b^3(2a^2-7ab+b^2)\cdot0=0$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3a^2b^3(2a^2-7ab+b^2)\cdot0& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(6a^4b^3-21a^3b^4+3a^2b^5)\cdot0 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}0a^4b^3+0a^3b^4+0a^2b^5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}0\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3a^2b^3} $ by $ \left( 2a^2-7ab+b^2\right) $ $$ \color{blue}{3a^2b^3} \cdot \left( 2a^2-7ab+b^2\right) = 6a^4b^3-21a^3b^4+3a^2b^5 $$ |
| ② | $$ \left( \color{blue}{6a^4b^3-21a^3b^4+3a^2b^5}\right) \cdot 0 = 0a^4b^30a^3b^40a^2b^5 $$ |
| ③ | Combine like terms: $$ 0 = 0 $$ |
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